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New Senior Secondary Learning as well as Teaching Resource List Subject Mathematics NSS Subject Resource List S4 Mathematics Summer Holiday Homework 2010 Mathematics ...
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New Senior Secondary Learning as well as Teaching Resource List Subject Mathematics NSS Subject Resource List S4 Mathematics Summer Holiday Homework 2010 Mathematics ...
Thanks for your answer Dr Buzz.. I calculated that at 1st but I need the HCl amount in mL. So i suspect im meant to use the V1 x M1 = V2 x M2 equation..
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Best Answer: molarity= number of moles/ volume (in L) 3.0 ml of the 0.25% solution contain 3 * 0.25 / 100 / 180 = 4.17 e5 mol divide this by 0.1 L to get 4.17 * 10 ...
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Best Answer: a. 7.5 mL b/c .10 M means .10 mol/1L which in proportion is 0.10mol/1000mL=xmol/150mL which then means there are .015 moles of NaCl Then we set up a new ...
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Author: Topic: 0.1 M HCL solution (Read 15905 times) 0 Members and 1 Guest are viewing this topic.